How Long to Read Compounds with Se, Te, Po

How Long Does it Take to Read Compounds with Se, Te, Po?

It takes the average reader 3 hours and 13 minutes to read Compounds with Se, Te, Po by Hartmut Bergmann

Assuming a reading speed of 250 words per minute. Learn more

Description

A fascinating aspect of many of the selenium- and tellurium-containing compounds described in this volume is that they are built up from octahedral Mo6 clusters which are surrounded by eight other atoms X in the form of a cube: Mo6X8. The Mo atoms occupy the centers of the faces of the X8 cube. The interesting variety in the substiution of the X positions can be encountered throughout the whole volume. The X atoms can be of a single element as in Mo6Te8, but can also be statistically occupied by two elements, e.g., in Mo6(Te,S)8, or even by more elements as in Mo6(Te,Se)8-yIy. In addition,...

How long is Compounds with Se, Te, Po?

Compounds with Se, Te, Po by Hartmut Bergmann is 192 pages long, and a total of 48,384 words.

This makes it 65% the length of the average book. It also has 59% more words than the average book.

How Long Does it Take to Read Compounds with Se, Te, Po Aloud?

The average oral reading speed is 183 words per minute. This means it takes 4 hours and 24 minutes to read Compounds with Se, Te, Po aloud.

What Reading Level is Compounds with Se, Te, Po?

Compounds with Se, Te, Po is suitable for students ages 10 and up.

Note that there may be other factors that effect this rating besides length that are not factored in on this page. This may include things like complex language or sensitive topics not suitable for students of certain ages.

When deciding what to show young students always use your best judgement and consult a professional.

Where Can I Buy Compounds with Se, Te, Po?

Compounds with Se, Te, Po by Hartmut Bergmann is sold by several retailers and bookshops. However, Read Time works with Amazon to provide an easier way to purchase books.

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